Revision ee345c39
Added by Hamish Coleman over 13 years ago
- ID ee345c394eb78c5ba96b8514ba0dfaf318ba85b9
| svctest.c | ||
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return 1;
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}
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char **env = environ;
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while(*env) {
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dprintf(1,"%s:%i: env==%s\n",__FILE__,__LINE__,*env);
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env++;
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}
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dprintf(1,"%s:%i: getenv(USERNAME)==%s\n",__FILE__,__LINE__,getenv("USERNAME"));
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char buf[100];
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int res = GetConsoleTitle(&buf,sizeof(buf));
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dprintf(1,"%s:%i: GetConsoleTitle()==%i, %s\n",__FILE__,__LINE__,
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res,buf);
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trace("return 0");
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return 0;
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}
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| win-scm.c | ||
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global_sd = sd;
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#if 0
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/* turns out to be untrue! */
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/* If we have commandline args, then we cannot have been started
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* by the Windows SCM
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/*
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* Attempt to detect if we have been run from an interactive session.
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* checking the environ is still not perfect, since if the
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* service is set to login as a user, it gets a USERNAME env
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* and if that user is currently logged in interactively, it
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* gets a SESSIONNAME env :-(
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* So, also check if there is a console window
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*
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* Other avenues of investigation:
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* from http://bytes.com/topic/net/answers/124885-multiple-use-exe-determine-if-running-service
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* - work out how System.Environment.UserInteractive works
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* - Check if parent process name is "services.exe"
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* from http://stackoverflow.com/questions/200163/am-i-running-as-a-service#200183
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*/
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if (argc>1) {
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char buf[100];
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if (getenv("USERNAME") && getenv("SESSIONNAME")
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&& GetConsoleTitle(&buf,sizeof(buf))) {
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return SCM_Start_Console(sd);
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}
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#endif
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/* try to run as a service */
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/*
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* Note, this will eventually fail if we are not started as a service
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* however, it will take an noticably long time to do so, thus we
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* try to short circuit this delay above.
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*/
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if (StartServiceCtrlDispatcher(ServiceTable)==0) {
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int err = GetLastError();
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Also available in: Unified diff
Update win-scm service detection from the svctest results