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Revision ee345c39

Added by Hamish Coleman about 14 years ago

  • ID ee345c394eb78c5ba96b8514ba0dfaf318ba85b9

Update win-scm service detection from the svctest results

View differences:

svctest.c
return 1;
}
char **env = environ;
while(*env) {
dprintf(1,"%s:%i: env==%s\n",__FILE__,__LINE__,*env);
env++;
}
dprintf(1,"%s:%i: getenv(USERNAME)==%s\n",__FILE__,__LINE__,getenv("USERNAME"));
char buf[100];
int res = GetConsoleTitle(&buf,sizeof(buf));
dprintf(1,"%s:%i: GetConsoleTitle()==%i, %s\n",__FILE__,__LINE__,
res,buf);
trace("return 0");
return 0;
}
win-scm.c
global_sd = sd;
#if 0
/* turns out to be untrue! */
/* If we have commandline args, then we cannot have been started
* by the Windows SCM
/*
* Attempt to detect if we have been run from an interactive session.
* checking the environ is still not perfect, since if the
* service is set to login as a user, it gets a USERNAME env
* and if that user is currently logged in interactively, it
* gets a SESSIONNAME env :-(
* So, also check if there is a console window
*
* Other avenues of investigation:
* from http://bytes.com/topic/net/answers/124885-multiple-use-exe-determine-if-running-service
* - work out how System.Environment.UserInteractive works
* - Check if parent process name is "services.exe"
* from http://stackoverflow.com/questions/200163/am-i-running-as-a-service#200183
*/
if (argc>1) {
char buf[100];
if (getenv("USERNAME") && getenv("SESSIONNAME")
&& GetConsoleTitle(&buf,sizeof(buf))) {
return SCM_Start_Console(sd);
}
#endif
/* try to run as a service */
/*
* Note, this will eventually fail if we are not started as a service
* however, it will take an noticably long time to do so, thus we
* try to short circuit this delay above.
*/
if (StartServiceCtrlDispatcher(ServiceTable)==0) {
int err = GetLastError();

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